Use Trigonometric identities to transform the left side of equation to right side. I'm DESPERATE FOR HELP!!!!?
1) (1+cosQ)(1-cosQ) = 1 - cos²Q = sin²Q 2) (secQ+tanQ)(secQ-tanQ) = sec²Q - tan²Q = 1/cos²Q - sin²Q/cos²Q = (1-sin²Q) / cos²Q = cos²Q/cos²Q = 1 3) sinQ/cosQ = sinQsecQ = secQ/cscQ (doesn't match your answer)
Use trigonometric identities to transform the left side of the equation into the right side?
Cotangent is the reciprocal of tangent. Cotθ = 1/tanθ. (tan θ)(1/tanθ) = 1 These will simplify to equal 1. 1=1
Use Trigonometric Identities to transform the left side ...?
Use Trigonometric Identities to transform the left side of the equation into the right side. I'll use O as theta. sinO/cosO + cosO/sinO = cscOsecO Could someone please show me the steps as to how I would transform this into cscOsecO=cscOsecO? Much appreciated. :)
Use trigonometric identities to transform the left side of the equation into the right side (0 (tanB + cotB) / tanB = tanB/tanB + cotB/tanB = 1 + (cosB/sinB)/(sinB/cosB) = 1 + (cosB/sinB)*(cosB/sinB) = 1 + cos²B/sin²B = sin²B/sin²B + cos²B/sin²B = (sin²B + cos²B)/sin²B = 1/sin²B = csc²B I hope that helps!
Use trigonometric identities to transform the left side of the equation to the right?
Use trigonometric identities to transform the left side of the equation to the right side (0<θ<π/2). tan α cos α = sin α I'm not really sure what to do, my professor gave us this problem for hw but we never went over anything like this and I can't find anything like it in the book.
Use trigonometric identities to transform one side of the equation into the other.?
I'll really appreciate any explanation on how to solve these problems. I have so many more to go. use trigonometric identities to transform one side of the equation into the other. 1. tan θ cot θ = 1 2. (1 + cos θ)(1 - cos θ) = sin^2 θ 3. (1+ sin θ)(1 - sin θ) = cos^2 θ 4. (sec θ + tan θ)(sec θ - tan θ) = 1 5. sin^2 θ - cos^2 θ = 2 sin^2 θ - 1 6. sinθ/cosθ + cosθ/sinθ = csc θ sec θ 7. tanθ + cotθ/ tanθ = csc^2 θ 8. tan θ cosθ = sin θ Thank you! :)
Math please help!! Use trigonometric identities to transform the left side of the equation to the right side.?
Cot α sin α sec α = 1, L.H.S. = Cot α sin α sec α = (cos α / sin α).sin α .(1 / cosα) = = 1 = R.H.S. >==================================< Q . E . D.
Use trigonometric identities to transform one side of the equation into the other (0<θ 1) (tanθ)*(1/tanθ) = 1 - cofunction identity for cotangent 2) (sinθ/cosθ)*(cosθ) = sinθ - cofunction identity for tangent 3) (1-cos^2(θ)) = sin^2(θ) - multiply using FOIL, pythagorean theorem (sin^2(θ) + cos^2(θ) = 1) 4) Multiple steps: Multiply left side by common denominator: (sinθcosθ)/(sinθcosθ) * [(sinθ/cosθ) + (cosθ/sinθ)] = sin^2(θ)/(sinθcosθ) + cos^2(θ)/(sinθcosθ) Combine fractions over common denominator: = (sin^2(θ) + cos^2(θ))/(sinθcosθ) Apply pythagorean identity: = 1/(sinθcosθ) "Pull apart" fraction by factoring: = 1/sinθ * 1/cosθ Cofunction identities for secant and cosecant: cscθ*secθ QED See sources for some really helpful free math tutoring videos.
How to use trig identities to transform one side of the equation into the other?
For the first one, expand the binomials on the left side. You can use the FOIL method, or whatever method you like best. (I'll use A for theta) (1 + cosA)(1 - cosA) = sin^2 A 1 - cosA + cosA - cos^2 A = sin^2 A 1 - cos^2 A = sin^2 A Using the pythagorean identity, we know that 1 - cos^2 A = sin^2 A. Therefore, the identity is proven. For the second one, the pythagorean theorem is used again. Since we know that sin^2 A + cos^2 A = 1, we can insert it into the equation where there is a 1, which is on the right side. sin^2 A + cos^2 A = 2sin^2 A - (sin^2 A + cos^2 A) Now you just simplify the right side by adding and subtracting like terms sin^2 A + cos^2 A = 2sin^2 A - sin^2 A - cos^2 A sin^2 A + cos^2 A = sin^2 A - cos^2 A Left side equals right side, therefore identity is true.
Use trig identities to transform one side of equation into other?
tan ø cot ø = 1 (sin ø/cos ø) (cos ø/sin ø) = 1